TRANSFORMERS MCQs SET 07
1. Third harmonic current in transformer at no-load is ______________
a) 3% of exciting current
b) 10% of exciting current
c) 25% of exciting current
d) 35% of exciting current
a) 3% of exciting current
b) 10% of exciting current
c) 25% of exciting current
d) 35% of exciting current
Answer: d
Explanation: The
effect of saturation nonlinearity is to create a family of odd-harmonic
components in the exciting current, the predominant being the third
harmonic; this may constitute as large as 35–40% of the exciting
current.
2. Ii in no-load test is responsible for ______________
a) Production of flux
b) Reactive power drawn from the supply
c) Active power drawn from the supply
d) No significance
a) Production of flux
b) Reactive power drawn from the supply
c) Active power drawn from the supply
d) No significance
Answer: c
Explanation:
It will be assumed here that the current Io and its magnetizing
component Im and its core-loss component Ii are sinusoidal on equivalent
rms basis. In other words, Im is the magnetizing current and is
responsible for the production of flux, while Ii is the core-loss
current responsible for the active power being drawn from the source to
provide the hysteresis and eddy-current loss.
3. The parallel circuit model is drawn because _________________
a) Conductance Gi accounts for core-loss current
b) Inductive susceptance Bm accounts for magnetizing current
c) Gi for core – loss current and Bm for magnetizing current
d) Cannot say
a) Conductance Gi accounts for core-loss current
b) Inductive susceptance Bm accounts for magnetizing current
c) Gi for core – loss current and Bm for magnetizing current
d) Cannot say
Answer: c
Explanation:
The parallel circuit model of exciting current can be easily imagined
wherein conductance Gi accounts for core-loss current Ii and inductive
susceptance Bm for magnetizing current Im. Both these currents are drawn
at induced emf E1 = V1 for resistance-less, no-leakage primary coil;
even otherwise E1 =V1.
4. A transformer cannot work on the DC supply because __________________
a) There is no need to change the DC voltage
b) A DC circuit has more losses
c) Faraday’s laws of electromagnetic induction are not valid since the rate of change of flux is zero
d) Cannot be determined
a) There is no need to change the DC voltage
b) A DC circuit has more losses
c) Faraday’s laws of electromagnetic induction are not valid since the rate of change of flux is zero
d) Cannot be determined
Answer: c
Explanation:
For DC supply the direction and the magnitude of the supply remains
constant, produced flux will be constant. Thus, rate of change of flux
through the windings will be equal to zero. As a result, voltage at
secondary will always be equal to 0.
5. An ideal transformer has infinite primary and secondary inductances.
a) True
b) False
a) True
b) False
Answer: b
Explanation:
The primary and secondary windings have zero resistance. It means that
there is no ohmic power loss and no resistive voltage drop in the ideal
transformer. An actual transformer has finite but small winding
resistances.
6. In a transformer the resistance between its primary and secondary is ______________
a) Zero
b) Very small
c) Cannot be predicted
d) Infinite
a) Zero
b) Very small
c) Cannot be predicted
d) Infinite
Answer: d
Explanation:
Since the primary and secondary windings are not connected to each
other, one can say there exists the resistance of infinite ohms. These
windings are connected to each other magnetically not electrically.
7. Identify the correct statement relating to the ideal transformer.
a) no losses and magnetic leakage
b) interleaved primary and secondary windings
c) a common core for its primary and secondary windings
d) core of stainless steel and winding of pure copper metal
a) no losses and magnetic leakage
b) interleaved primary and secondary windings
c) a common core for its primary and secondary windings
d) core of stainless steel and winding of pure copper metal
Answer: a
Explanation:
There is no leakage flux so that all the flux is confined to the core
and links both the windings. An actual transformer does have a small
amount of leakage flux which can be accounted in detailed analysis by
appropriate circuit modelling.
8. An ideal transformer will have maximum efficiency at a load such that _____________
a) copper loss = iron loss
b) copper loss < iron loss
c) copper loss > iron loss
d) cannot be determined
a) copper loss = iron loss
b) copper loss < iron loss
c) copper loss > iron loss
d) cannot be determined
Answer: a
Explanation: Maximum
efficiency of a transformer is defined at the that values when, copper
losses become completely equal to the iron losses. In all other cases
the efficiency will be lower than the maximum value.
9. Which of
the following statement regarding an ideal single-phase transformer is
incorrect? Transformer is having a turn ratio of 1: 2 and drawing a
current of 10 A from 200 V AC supply is incorrect?
a) It’s a step-up transformer
b) Its secondary voltage is 400 V
c) Its rating is 2 kVA
d) Its secondary current is 20 A
a) It’s a step-up transformer
b) Its secondary voltage is 400 V
c) Its rating is 2 kVA
d) Its secondary current is 20 A
Answer: d
Explanation:
Since turns ratio is equal to 1:2 the transformer will give higher
voltage at secondary with respect to the primary voltage, and current in
secondary thus will be halved. In last option current is doubled which
is opposite to the ratings given.
10. Ideal transformer core has permeability equal to _____
a) Zero
b) Non-zero finite
c) Negative
d) Infinite
a) Zero
b) Non-zero finite
c) Negative
d) Infinite
Answer: d
Explanation:
The core has infinite permeability so that zero magnetizing current is
needed to establish the requisite amount of flux in the core. The
core-loss (hysteresis as well as eddy-current loss) is considered zero.
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