DIGITAL ELECTRONICS MCQS PART 01
1. The NAND gate output will be low if the two inputs are
(A) 00
(B) 01
(C) 10
(D) 11
Ans: D
2.What is the binary equivalent of the decimal number 368
(A) 101110000
(B) 110110000
(C) 111010000
(D) 111100000
Ans: A
3. The decimal equivalent of hex number 1A53 is
(A)6793
(B) 6739
(C) 6973
(D) 6379
Ans: B
4. (734)8 = ( )16
(A) C 1 D
(B) D C 1
(C) 1 C D
(D) 1 D C
Ans: D
5. The simplification of the Boolean expression (ABC)+ (ABC) is
(A) 0
(B) 1
(C) A
(D) BC
Ans: B
6. The number of control lines for a 8 – to – 1 multiplexer is
(A) 2
(B) 3
(C) 4
(D) 5
Ans: B
7. How many Flip-Flops are required for mod–16 counter?
(A) 5
(B) 6
(C) 3
(D) 4
Ans: D
8. EPROM contents can be erased by exposing it to
A. Ultraviolet rays.
B.Infrared rays.
C. Burst of microwaves.
D.Intense heat radiations
Ans: A
10. The hexadecimal number ‘A0’ has the decimal value equivalent to
(A) 80
(B) 256
(C) 100
(D) 160
Ans: D
(A) 00
(B) 01
(C) 10
(D) 11
Ans: D
2.What is the binary equivalent of the decimal number 368
(A) 101110000
(B) 110110000
(C) 111010000
(D) 111100000
Ans: A
3. The decimal equivalent of hex number 1A53 is
(A)6793
(B) 6739
(C) 6973
(D) 6379
Ans: B
4. (734)8 = ( )16
(A) C 1 D
(B) D C 1
(C) 1 C D
(D) 1 D C
Ans: D
5. The simplification of the Boolean expression (ABC)+ (ABC) is
(A) 0
(B) 1
(C) A
(D) BC
Ans: B
6. The number of control lines for a 8 – to – 1 multiplexer is
(A) 2
(B) 3
(C) 4
(D) 5
Ans: B
7. How many Flip-Flops are required for mod–16 counter?
(A) 5
(B) 6
(C) 3
(D) 4
Ans: D
8. EPROM contents can be erased by exposing it to
A. Ultraviolet rays.
B.Infrared rays.
C. Burst of microwaves.
D.Intense heat radiations
Ans: A
10. The hexadecimal number ‘A0’ has the decimal value equivalent to
(A) 80
(B) 256
(C) 100
(D) 160
Ans: D
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